Easy ways to check Armstrong number in java

An Armstrong number is an n-digit number that is equal to the sum of the n^th powers of its digits.

e.g –

Numbers 1 to 9 (1 digit, so to the power 1)

1^1 = 1, 2^1 = 2, 3^1 = 3

Number 371 (3 digit, so to the power 3)

371 is of 3 digits, so sum of each digits cube should be 371

3^3 + 7^3 + 1^3 = 27 + 343 + 1 = 371

Number 1634 (4 digit, so to the power 4)

1^4 + 6^4 + 3^4 + 4^4 = 1 + 1296 + 81 + 256 = 1634

Let’s see implementation in java

public class Armstrong {

	public static void main(String[] args) {
		
		Scanner s = new Scanner(System.in); //371
		System.out.println("enter a number - ");
		int number = s.nextInt();
		int sum=0, rem;
		
		for (int i = number; i > 0; i = i / 10)
		{
		    rem = i % 10;
		    sum = sum + rem * rem *rem;
		}
		if(sum==number)
		{
		     System.out.println(number + " is an Armstrong Number\n");
		}
		s.close();
	}
}